01.07.2007, 22:06
Hi all,
As promised, here is a 'walkthrough' for my ABC'tje.
I received a PN from someone who got stuck, and I know that he is very well able to solve this kind of puzzles. So maybe it was a bit too hard. Anyhow, here we go:
michaela - michael; a = 11
marina - maria; n = 7
annette - a - n; te = 37
baars - aa; brs = 47
bartelsen-brs-et-a-n; el = 30
axel; x = 21
boser- brs; oe = 35
ballas - a; blls = 37
oliver - el; vior = 58
arvid - a; vidr = 35
brs versus blls; LL + 10 = R :=> L max. 8
With these subresult we can create a table:
L E O T D R
8 22 13 15 21 26
7 23 12 14 20 24
6 24 11 13 19 22
5 25 10 12 18 20
4 26 9 11 17 18
Because of the values already used, only the line of L = 5 is valid and we know immediately 6 letters.
We go on:
terwen; w = 26
radtke; k = 15
doerffer; f = 13
gross; gss = 64
G and S maximal 24 (25 and 26 are used)
G has to be even
New table:
G S
24 20
22 21
20 22
18 23
16 24
Because of used values: G = 16; S = 24
Ellinger; i = 9
brs; b = 3
vior; v = 19
helge; h = 17
maria; m = 23
michael; c = 6
claudia; u = 4
jung; j = 22
strempel; p = 8
krzysztof; yzz = 5
Values left: 1, 2, 14
Y = 1; Z = 2
And finally left: Q = 14
I hope you had fun with it.
I have another idea in mind for a nice 'optimising puzzler names puzzle' and will work it out in my summer holiday. I will send it to Berni afterwards.
Regards,
Richard
As promised, here is a 'walkthrough' for my ABC'tje.
I received a PN from someone who got stuck, and I know that he is very well able to solve this kind of puzzles. So maybe it was a bit too hard. Anyhow, here we go:
michaela - michael; a = 11
marina - maria; n = 7
annette - a - n; te = 37
baars - aa; brs = 47
bartelsen-brs-et-a-n; el = 30
axel; x = 21
boser- brs; oe = 35
ballas - a; blls = 37
oliver - el; vior = 58
arvid - a; vidr = 35
brs versus blls; LL + 10 = R :=> L max. 8
With these subresult we can create a table:
L E O T D R
8 22 13 15 21 26
7 23 12 14 20 24
6 24 11 13 19 22
5 25 10 12 18 20
4 26 9 11 17 18
Because of the values already used, only the line of L = 5 is valid and we know immediately 6 letters.
We go on:
terwen; w = 26
radtke; k = 15
doerffer; f = 13
gross; gss = 64
G and S maximal 24 (25 and 26 are used)
G has to be even
New table:
G S
24 20
22 21
20 22
18 23
16 24
Because of used values: G = 16; S = 24
Ellinger; i = 9
brs; b = 3
vior; v = 19
helge; h = 17
maria; m = 23
michael; c = 6
claudia; u = 4
jung; j = 22
strempel; p = 8
krzysztof; yzz = 5
Values left: 1, 2, 14
Y = 1; Z = 2
And finally left: Q = 14
I hope you had fun with it.
I have another idea in mind for a nice 'optimising puzzler names puzzle' and will work it out in my summer holiday. I will send it to Berni afterwards.
Regards,
Richard