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Not in German sorry but no advanced technique needed. Further pencil marking would allow you to see that there is a 36 pair in column 4. This will impact where you're able to place 6 in row 9 and allow you to place a digit. The rest of the puzzle should flow from there.
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No problem. In r2c4 and r5c4, the only two digits that can go in these squares are 3 or 6. Therefore, the numbers 3 and 6 must go in these two squares in column 4 and cannot be placed elsewhere in the column (e.g. if a 3 was placed in r1c4 instead, and a 6 was placed in r2c4, then you wouldn't be able to place anything in r5c4 and the puzzle would break).
Currently, the only numbers that can go in r9c4 are 4, 6 and 8. However, as 3 and 6 must be located elsewhere in column 4 (rows 2 and 4), we know that 6 cannot be placed in r9c4.
There's then two ways that you can look at things. First, you can recognise that the only places in box 8 that a 6 can now go is in row 7. Using the 6 that's placed in box 9, this means the 6 must be placed in r9c1 in box 6. Alternatively, you can just think about where the 6 can be placed in row 9 after you've ruled it out from being placed in r9c4: given the 6 that's already in box 9, again, the only place in r9 for the 6 is r9c1.
I'm by no means a sudoku expert and it looks like your pencil marking style is different to mine, but I'd recommend that when you get stuck you place more pencil markings and then look out for more doubles and triples that you otherwise are very unlikely to spot. Other, more complex techniques will also require you to do some more pencil marking to be able to spot the patterns.